http://imageshack.us/photo/my-images/528/circuito.png/
http://img528.imageshack.us/img528/3585/circuito.png
find the effecive resistance..
thanks, and sorry for the other thread, i cant edit it...
How come you couldn't post this sketch to other thread? You don't need to "edit" your original message. Just post a reply to the other thread with this sketch.
http://imageshack.us/photo/my-images/528/circuito.png/
http://img528.imageshack.us/img528/3585/circuito.png
find the effecive resistance..
thanks, and sorry for the other thread, i cant edit it...
Hey thanks, yupp, it is exactly like that.Your original diagram looks like fig A and I redrawn it as fig B. In the redrawn diagram, R15 and R13 are in series and you can replace them with just one resistor. R16 & R17 are in parallel and can also be replaced with one resistor.
I hope the final diagram after simplification is easy for you to solve.
Allen
hi, i read the reply from you from the other thread.I think the upper left resistor is 6Ω.
Do you know the technique (equation) for combining 3 resistors in parallel? Combine R14, R18, and R19. Just because there are other parallel combinations doesn't mean you can't combine those 3.Hey thanks, yupp, it is exactly like that.
I have redrawn my diagramme to Figure B, and i cant solve from there.
The problem is that it seems that 18,19,14 are in parallel, and 17 and 16 are in parallel.
But isnt it that 18, 19, 17 and 16 are all in parallel as well? Because i use the current from the source and as long as there is a split or current (node), i assume that the two elements are in parallel, which work perfectly with other circuits.
But not this one..
Hi thanks again..Do you know the technique (equation) for combining 3 resistors in parallel? Combine R14, R18, and R19. Just because there are other parallel combinations doesn't mean you can't combine those 3.
Components are in parallel if they are connected together at BOTH ends, not just one.Hey thanks, yupp, it is exactly like that.
I have redrawn my diagramme to Figure B, and i cant solve from there.
The problem is that it seems that 18,19,14 are in parallel, and 17 and 16 are in parallel.
But isnt it that 18, 19, 17 and 16 are all in parallel as well? Because i use the current from the source and as long as there is a split or current (node), i assume that the two elements are in parallel, which work perfectly with other circuits.
But not this one..
This is very hard to follow, but I think I deciphered it.For example, when the current enters the first node, splitting into right, down(12ohm) and left(6 ohm), the current along the left circuit, does it travel straight to the end voltage? Because it encounters another node right? shouldnt it split too, before it encounter the 4 ohm resistor??