parallel inductance capacitance

Discussion in 'Homework Help' started by regexp, Nov 20, 2010.

  1. regexp

    Thread Starter New Member

    Nov 20, 2010

    I need to find the resulting vector of a resistor in parallel with a capacitance in parallel with an inductance.

    The complex impedances are -J50 and J200. The value of the resistor is 100Ω

    So i have  \frac{1}{\frac{1}{100}+\frac{1}{-j50}+\frac{1}{j200}}

    In the key to my textbook this should equate to 55.47\angle -56.31.

    And i don't get that...

    if I add the two complex impedances i have 100 + J150.

    \frac{1}{1/100 +1/150} = 60 \angle 56.31
  2. t_n_k

    AAC Fanatic!

    Mar 6, 2009
    The text answer is correct - you need to re-check your method.

    The components are in parallel - not in series. Adding the two complex terms as you have done would be OK if they in series.