Think I have found one that I can play with a bit.

Current limiting resistor

5-1.15/.01=385 ohm, 390 ohm standard.

Load resistor

5-(0.7+2.0)/.01=230 ohm, 240 ohm standard.

Basically the same as you posted previously, but now I can change it up a bit.

Current limiting resistor

24-1.15/.01=2285 ohm, 2.4k, e24

Load resistor

24-(0.7+2.0)/.01=2130 ohm 2.2k, e24

Still need to learn a bit more on using datasheets, but I think I have this correct using your numbers for the LED.

 

It is not a good idea to use my username in the title, as it may discourage others from attempting to answer your question; and I may be offline for awhile very soon.

It would have been better if you had simply replied to the original thread, here:
http://forum.allaboutcircuits.com/showthread.php?t=52375
Hopefully a Moderator will append these messages to that thread.

Current limiting resistor
5-1.15/.01=385 ohm, 390 ohm standard.

This looks OK.

Load resistor

5-(0.7+2.0)/.01=230 ohm, 240 ohm standard.

I guess you're talking about LED1 and R2 in this schematic:

If so, then you're OK.

Current limiting resistor

24-1.15/.01=2285 ohm, 2.4k, e24

If you're talking about the IR emitter side being supplied with 24v and a current of 10mA, then you're fine.

Load resistor

24-(0.7+2.0)/.01=2130 ohm 2.2k, e24

Yes, that works too.

Don't forget to calculate the power requirements for the current limiting resistors.
For example, the 24v supply on the IR emitter side:
P=EI
P=(24-1.15)*((24-1.15)/2400)
P= 22.85 * (22.85/2400)
P = 22.85 * 9.52mA
P = 218mW
Now, for reliability's sake, we multiply the result by 1.6
2.18*1.6 = 348mW
1/4 Watts is not enough, you'd need to use 1/2 Watt rated resistors. If you tried it with 1/4 Watt resistors, they would get quite warm, and the reliability would suffer.

 

noted.

thanks for the help.

Jim