At those speeds without very careful layout and impedance control your expectations for a "clean square wave" are quite simply unreasonable.Hi all,
I am using a 80 MHz crystal oscillator. What I am seeing a 3V negative undershoot and a 2V positive overshoot. I am using 5V Vcc. Also I am not seeing a clean square wave.
Can somebody help me.
Even with a perfect (zero impedance) voltage source, this will happen. The current into the probe's capacitance must return to the probe tip through the ground lead of the probe. If this is a 6 inch wire, the inductance will probably be over 100nH - possibly over 200nH. The ringing is due to the ground wire. It may be exacerbated by the inductance of the trace being probed.Ron makes an excellent point. It is often the case that observation for the purpose of measurement significantly changes the system under observation. As an exercise you might want to compute the reactance of the trace inductance at that frequency. I think you'll be surprised.
Good point, except at 80MHz, the probe compensation cap will probably cause the amplitude of the entire waveform to change - not just the edges. It would be worth checking out.Are you using a "Times 10" probe? If you are, have you tried adjusting the capacitor on the probe?
|Thread starter||Similar threads||Forum||Replies||Date|
|F||Stabilize a system, so there is an overshoot of 10%||Homework Help||0|
|overshoot and stability issue||Analog & Mixed-Signal Design||12|
|Inductive kick/spike without overshoot||Power Electronics||7|
|How to calculate the required filter frequency to remove a certain overshoot||Analog & Mixed-Signal Design||14|
|voltage overshoot in capacitive circuits||General Electronics Chat||2|