# Overlap theorem

#### AntonioDuarte2001

Joined Nov 1, 2020
47
In this exercise is asked to calculate "I" using the overlap theorem.
Something is wrong with my resolution, because the final answer is wrong.

Mod: rotated image and cleaned up.E

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#### AlbertHall

Joined Jun 4, 2014
12,023
In your second diagram, the calaculation shows 3A flowing in 6Ω. Is that right?

#### AntonioDuarte2001

Joined Nov 1, 2020
47
In your second diagram, the calaculation shows 3A flowing in 6Ω. Is that right?
Yes sir.

#### AlbertHall

Joined Jun 4, 2014
12,023
So no part of that 3A flows through the 2Ω and 8Ω resistors?

#### Deleted member 115935

Joined Dec 31, 1969
0
Overlap theorem ?

Just for my information, long time since I have done this,

Is this the one where you one by one replace current sources by an open circuit, and voltage sources by a short,

then sum the current / volts in the circuits ?

#### AntonioDuarte2001

Joined Nov 1, 2020
47
So no part of that 3A flows through the 2Ω and 8Ω resistors?
Some part i think. But what are you trying to say?

#### AntonioDuarte2001

Joined Nov 1, 2020
47
Overlap theorem ?

Just for my information, long time since I have done this,

Is this the one where you one by one replace current sources by an open circuit, and voltage sources by a short,

then sum the current / volts in the circuits ?
Yes it is.

#### AlbertHall

Joined Jun 4, 2014
12,023
Some part i think. But what are you trying to say?
What I am trying to say is that in the second calculation you calculaye 18V as if all of the 3A is flowing in the 6Ω resistor but as the current is shared with the other branch then that 18V is incorrect.