optocoupler (MCT2E) resistor?

Thread Starter

onlyvinod56

Joined Oct 14, 2008
363
Hello.

I need to connect MCT2E optocoupler to F28335 DSP board whose logic high voltage is 3.3V.

What value of resistor should be used on emitter side?
Thankyou.
 

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ericgibbs

Joined Jan 29, 2010
8,733
hi,
The MCT emitter has a forward drop of 1.25V, so I would design for a current of 10mA.

Thats 3.3 -1.25 = 2.05/.01 =~200R, use a 180R or 220R.
 

THE_RB

Joined Feb 11, 2008
5,430
The "3.3v logic high" sourcing 10mA will be more like 2.8 or 2.9v DC.

2.8v - 1.25 LED Vf = 1.55v
R = E/I = 1.55/10 = 155 ohm.

I would probably go with 180 ohm like Ericgibbs suggested and see how it works.

The moment you connect it to the logic high pin, you can measure the volts across the resistor because the LED is on and the resistor volts can tell you the LED current; I = E/R = ?/180 ohm
 
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