# optics fourier transform definition question

#### yef smith

Joined Aug 2, 2020
381
Hello the basic fourier transform in optics is developed as shown bellow where F is the fourer transform operator and Q is the exponent expression.
But later when we use the tranform on actual source we get an expression with fx fy variable defined as shown bellow.
i know that K=2*pi*f as shown in the last expression bellow
how they got the shown bellow f_x to x relations in the optical furier transform?
Thanks.

#### Deleted member 115935

Joined Dec 31, 1969
0
HOme work ?