I am really struggling with this topic...

(a) is it infinite input resistance in this so the I in = 0?
(b) is that "differential inputs stick together"? but I think that Vp and Vn are not an input.
(c) I have no idea how to deal with the resistors below 16k (4k & 6k). can I treat them as series and parallel to sum them up?
(d,e) can someone show me the steps and answers with some explanations please?

Many thanks!!!

 

(a) Correct.

(b) If Vp and Vn are not inputs (to the opamp), what would you say are? Remember, the question isn't asking anything about Vp or Vn individually, it is only asking about the difference between Vp and Vn.

(c) Can you treat them as "series AND parallel"? What do you mean by that?

(d,e) How many nodes do you have in the circuit? Can you write equations relating them to each other?

Make and post your best attempt and we can proceed from there.

 

For d you will probably want to redraw the circuit using hybrid pi model of op-amp. Should be in your textbook, somewhere.

 

(a) Correct.

(b) If Vp and Vn are not inputs (to the opamp), what would you say are? Remember, the question isn't asking anything about Vp or Vn individually, it is only asking about the difference between Vp and Vn.

(c) Can you treat them as "series AND parallel"? What do you mean by that?

(d,e) How many nodes do you have in the circuit? Can you write equations relating them to each other?

Make and post your best attempt and we can proceed from there.

(b) so if it is then Vp and Vn are the same and subtracting them would be zero?

(c) sorry I mean series or parallel. if I do
(16*4)/(16+20) = 3.2 k ohms
3.2+6 = 9.2 k ohms
would that be correct?

if the above is correct then using nodal analysis

(Vn-Vx)/4 + (Vn-Vout)/9.2 = 0
then I can get the Vout?

(e) really have no clue where to start from, is there any formula for the saturation?

thanks a lot for helping

 

For d you will probably want to redraw the circuit using hybrid pi model of op-amp. Should be in your textbook, somewhere.

never seen that before, I think thats not covered in my course.

 

(c) sorry I mean series or parallel. if I do
(16*4)/(16+20) = 3.2 k ohms
3.2+6 = 9.2 k ohms
would that be correct?

c is asking you to express Vp in terms of Vout.
Do you see any Vp in what you wrote? Do you see any Vout in what you wrote?

I don't.

 

never seen that before, I think thats not covered in my course.

What textbook are you using?

 

c is asking you to express Vp in terms of Vout.
Do you see any Vp in what you wrote? Do you see any Vout in what you wrote?

I don't.

I am assuming Vn and Vp are the same but Im not sure about that.
is that should be
(Vp-Vx)/4 + (Vp-Vout)/9.2 = 0
?

What textbook are you using?

We just use the notes that the lecturer issued.

 

I am assuming Vn and Vp are the same but Im not sure about that.
is that should be
(Vp-Vx)/4 + (Vp-Vout)/9.2 = 0
?

(c) Use voltage division to express Vp as a fraction of Vout.

The Vn is not involved. The Vx is not involved.

Vout is voltage from op-amp output to ground. 4k and 6k are resistors from op-amp output to ground. Draw this circuit. Mark Vp on the circuit. Express Vp in terms of Vout.

 

I am assuming Vn and Vp are the same but Im not sure about that.
is that should be
(Vp-Vx)/4 + (Vp-Vout)/9.2 = 0
?


We just use the notes that the lecturer issued.

You don't need to assume anything about Vn or Vx.

You have a voltage at the output, namely Vout.

You have two resistors, a 4kΩ and a 6kΩ, connecting Vout to ground.

There is a connection from the junction of the two resistors that goes to the Vp input of the opamp.

Q1) What is the current going into the Vp input of the opamp?

Q2) Given the answer to Q1, what is the current in the two resistors?

Q3) Given the answer to Q2, what is the voltage at the Vp input of the opamp?

 

(c) Use voltage division to express Vp as a fraction of Vout.

The Vn is not involved. The Vx is not involved.

Vout is voltage from op-amp output to ground. 4k and 6k are resistors from op-amp output to ground. Draw this circuit. Mark Vp on the circuit. Express Vp in terms of Vout.

(Vout - Vp)/4 + (Vout - 0)/10 = 0
is this correct?

You don't need to assume anything about Vn or Vx.

You have a voltage at the output, namely Vout.

You have two resistors, a 4kΩ and a 6kΩ, connecting Vout to ground.

There is a connection from the junction of the two resistors that goes to the Vp input of the opamp.

Q1) What is the current going into the Vp input of the opamp?

Q2) Given the answer to Q1, what is the current in the two resistors?

Q3) Given the answer to Q2, what is the voltage at the Vp input of the opamp?

is it 0 if it is connecting to the ground?

 

(Vout - Vp)/4 + (Vout - 0)/10 = 0
is this correct?

Draw the circuit and post it.

 

Draw the circuit and post it.

 

For d you will probably want to redraw the circuit using hybrid pi model of op-amp. Should be in your textbook, somewhere.

What are you talking about? Why do we need any "model" to find Vout for Vin = 6V ?

 

Wrong.

The correct circuit is this:

Where does the Vp go?

 

What are you talking about? Why do we need any "model" to find Vout for Vin = 6V ?

Well, for one thing I assumed they had a proper textbook. You have probably noticed that the particular assumption has bitten me on my ass.

At this point I will just help with stuff I know.

 

Wrong.

The correct circuit is this:

Where does the Vp go?

is it at the middle of the resistors?

 

is it at the middle of the resistors?

In the resistive network like this one, you would say Voltage X is across Resistor Y.

So. Where is Vp?

 

In the resistive network like this one, you would say Voltage X is across Resistor Y.

So. Where is Vp?

Vp is across 4k resistor?

is it Vp = (Vout*4)/(4+6)

 

Vp is across 4k resistor?

is it Vp = (Vout*4)/(4+6)

Seriously?

Look at the pic in your problem. Work from the output of the op-amp toward the ground.

At the output of the op-amp we have 4k resistor, there will be some voltage across the 4k resistor. Is it Vp?

From the 4k resistor we have another resistor, the 6k. There will be some voltage drop across the 6k resistor. Is it Vp?