Op-Amp Oscillator

Discussion in 'Homework Help' started by Mesatay, Mar 24, 2011.

  1. Mesatay

    Thread Starter New Member

    Mar 23, 2011
    I was was viewing the forums to find help with a problem. What I found was a pdf file someone posted with the exact answer I was looking for. What I am a bit confused on still is where the dV = 2Va and the dt = 1/2f comes from. If someone could look at the attached pdf and help me out, I would greatly appreciate it. Thank you very much.
  2. t_n_k

    AAC Fanatic!

    Mar 6, 2009
    The dV term is just the integrator output (triangle) wave peak-to-peak range. The dt term is half the triangle wave period. In other words the integrator output swings from +Va to -Va for one half of the waveform cycle and from -Va to +Va for the other half cycle.
  3. Fraser_Integration


    Nov 28, 2009
    This was my original question ha ha. Brings back memories!

    Yes to re-iterate tnk's point, the integrator goes from -Va to + Va (which is 2Va) in half a cycle (i.e. dt = T/2 = 1/2f)