(This question comes from some comments made in the thread Easiest way to detect sound.)
I have really one major question and one minor question.
Question #1, Minor question:
Is there such a thing as an inverting op amp and noninverting op amp?
I understand that an inverting amplifier and noninverting amplifier are just two configurations of circuit constructed with an op amp (the op amp itself being potentially an identical device in either configuration). Audioguru keeps mentioning a inverting op amp but I don't understand. Now, perhaps inverting op amp is just an imprecise shorthand for inverting amplifier build with an op amp, but that is not clear to me. (For reference, I have read the AAC op amp chapter and specifically been looking at the divided feedback section.)
Question #2, Major question:
What is the input impedance of an op amp based amplifier circuit?
Does an inverting amplifier have a lower input impedance than an inverting amplifier? After reading the AAC Op-Amp chapter, I did not find any mention of the fact that an inverting amplifier configuration of op-amp has a lower input impedance. In fact, I first thought that op amp amplifiers would have a very high input impedance, since it is a distinguishing characteristic of the op amp inputs that they have nearly infinite impedance (theoretically infinite in simple model).
But looking at the inverting amplifier divided feedback circuit it is clear that the op amp output voltage has a finite impedance to the amplifier input signal, due to the two resistors in series between these points. That seems to indicate that with, for instance, the first amplifier circuit, a noninverting amplifier, on the Divided feedback page (Figure 1, see below) would have a very high input impedance (ideally infinite) because the input signal (the 6 V battery) is directly connected only to the op amp noninverting input.
Figure 1: Noninverting amplifier circuit.
On the other hand, an inverting amplifier appears that it would have a low input impedance due to the current that would flow from the input signal (again, the 6 V battery) to the op amp output through the two divider resistors (see Figure 2, below).
Figure 2: Inverting amplifier circuit.
It sounds like the AAC Operational Amplifiers chapter could benefit from a note about the significant difference in input impedance between noninverting and inverting amplifier circuits. This is likely going to be a critical factor in the choice of op amp circuit used for many applications.
(On the topic of this AAC page, Vol III > Op amps > Divided feedback, I think that the battery symbol showing the input voltage to the op amp could be more clearly indicated as the input signal to be amplified rather than just a battery with 6 V label.) When this input signal moves around e.g. between the inverting and noninverting amplifier circuits, it is to me not immediately clear from where the input signal is coming.)
I have really one major question and one minor question.
Question #1, Minor question:
Is there such a thing as an inverting op amp and noninverting op amp?
I understand that an inverting amplifier and noninverting amplifier are just two configurations of circuit constructed with an op amp (the op amp itself being potentially an identical device in either configuration). Audioguru keeps mentioning a inverting op amp but I don't understand. Now, perhaps inverting op amp is just an imprecise shorthand for inverting amplifier build with an op amp, but that is not clear to me. (For reference, I have read the AAC op amp chapter and specifically been looking at the divided feedback section.)
Well, the AAC op amp chapter clearly does talk about noninverting and inverting amplifiers using divided negative feedback. If it does not talk about inverting and non-inverting opamps, then what exactly is an inverting or non-inverting opamp???No. It does not talk about inverting and non-inverting opamps.Wow, that is an important distinction that I have not realized before. Is this mentioned in the AAC op amp chapter??
Question #2, Major question:
What is the input impedance of an op amp based amplifier circuit?
Does an inverting amplifier have a lower input impedance than an inverting amplifier? After reading the AAC Op-Amp chapter, I did not find any mention of the fact that an inverting amplifier configuration of op-amp has a lower input impedance. In fact, I first thought that op amp amplifiers would have a very high input impedance, since it is a distinguishing characteristic of the op amp inputs that they have nearly infinite impedance (theoretically infinite in simple model).
But looking at the inverting amplifier divided feedback circuit it is clear that the op amp output voltage has a finite impedance to the amplifier input signal, due to the two resistors in series between these points. That seems to indicate that with, for instance, the first amplifier circuit, a noninverting amplifier, on the Divided feedback page (Figure 1, see below) would have a very high input impedance (ideally infinite) because the input signal (the 6 V battery) is directly connected only to the op amp noninverting input.

Figure 1: Noninverting amplifier circuit.
On the other hand, an inverting amplifier appears that it would have a low input impedance due to the current that would flow from the input signal (again, the 6 V battery) to the op amp output through the two divider resistors (see Figure 2, below).

Figure 2: Inverting amplifier circuit.
It sounds like the AAC Operational Amplifiers chapter could benefit from a note about the significant difference in input impedance between noninverting and inverting amplifier circuits. This is likely going to be a critical factor in the choice of op amp circuit used for many applications.
(On the topic of this AAC page, Vol III > Op amps > Divided feedback, I think that the battery symbol showing the input voltage to the op amp could be more clearly indicated as the input signal to be amplified rather than just a battery with 6 V label.) When this input signal moves around e.g. between the inverting and noninverting amplifier circuits, it is to me not immediately clear from where the input signal is coming.)