What is wrong with my thoughts? I am trying to explain the formula bellow in an other way.
I understand the formula well and how it is derived.
Now I want to try it in other way.
At first(t=0), assume that the voltage across the capacitor is zero.
Vc(0) = 0V
=> Vout(0) = -A (-Vos) = A*Vos.
This output voltage is feeded to the input and C is charged to A*Vos.
Vc(t1) = A*Vos
Now Vout(t1) = -A*(A*Vos - Vos) = -A(A-1)*Vos.
=> Vc(t2) = -A(A-1)*Vos
And here is the voltage across the capacitor C in time:
t = 0: Vc(0) = 0V
t=t1: Vc(t1)= A*Vos V
t=t2: Vc(t2)=-A(A-1)*Vos V
Here is what confuse me.
In the picture formula Vc = A/(A+1) * Vos and it is clear that it is a constant but what I found is a varying voltage in time.
Could you tell me what I am wrong here?
I understand the formula well and how it is derived.
Now I want to try it in other way.
At first(t=0), assume that the voltage across the capacitor is zero.
Vc(0) = 0V
=> Vout(0) = -A (-Vos) = A*Vos.
This output voltage is feeded to the input and C is charged to A*Vos.
Vc(t1) = A*Vos
Now Vout(t1) = -A*(A*Vos - Vos) = -A(A-1)*Vos.
=> Vc(t2) = -A(A-1)*Vos
And here is the voltage across the capacitor C in time:
t = 0: Vc(0) = 0V
t=t1: Vc(t1)= A*Vos V
t=t2: Vc(t2)=-A(A-1)*Vos V
Here is what confuse me.
In the picture formula Vc = A/(A+1) * Vos and it is clear that it is a constant but what I found is a varying voltage in time.
Could you tell me what I am wrong here?
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