I need to find Norton Eqivalent by 1 kΩ resistor and then find http://imageshack.us/photo/my-images/37/40362225.png/ So I first calculated the short circuit current where the 1kΩ resistor was. Since in the situation would be 0V because of the short dependent source would be gone shorting out the 3.3kΩ resistor and 680Ω resistor. And then I would have After that I need to calculate which is So I put a 1V test source and in the direction of the voltage rise. The 1V test source is - toward bottom and + towards top of circuit. So then this gives me Since is in parallel with my test source but in opposite direction So I end up with So Divided by gives me which I get to equal .667Ω So I set up the Norton Equivalent and then need to solve for which I am not 100% on but I was thinking it would just be the voltage of the Norton Equivalent. So I changed it to a Thevenin Equivalent and got Then answer in the textbook is I want to know where I went wrong as my answer is no where near the right answer. I sorry I don't have any pictures of my work, it was hard to take a good picture of it.
Your Rth calculation is flawed for sure as the resultant is about the 4.7K||3.98K which can never be in the lower end to the best of my knowledge