Hi all,
I'm (trying) to teach myself some digital circuitry and I thought I'd give this forum a go for some understanding. Before you all get your knickers in a twist, I did search the forums and looked at the online textbook, I'm currently working from Floyd's, Digital Fundamentals. There's not much out on the Net that makes sense to me, I could may well be backward!
It's a fairly simple question. I'm trying to grasp the universality of NOR gates by doodling some circuits from Boolean expression that I scrounge up from where ever. I came across one that made me feel my understanding of Boolean Algebra was shaky:
X = (AB' + C')EG + (KF + HA)I'
I'm only interested in the following part at the moment:
AB'
Given:
2 input AND gate = AB
2 input NAND gate = (AB)'
2 input OR gate = A+B
2 input NOR gate = (A+B)'
AA = A
A'A' = A'
De Morgan's Theorem:
(A+B)' = A'B'
(AB)' = A'+B'
I drew this as the equivalent of an AND gate:
Then I drew this for AB', but my gut says something is wrong:
Is it correct?
Nomnom,
k00k1e
I'm (trying) to teach myself some digital circuitry and I thought I'd give this forum a go for some understanding. Before you all get your knickers in a twist, I did search the forums and looked at the online textbook, I'm currently working from Floyd's, Digital Fundamentals. There's not much out on the Net that makes sense to me, I could may well be backward!
It's a fairly simple question. I'm trying to grasp the universality of NOR gates by doodling some circuits from Boolean expression that I scrounge up from where ever. I came across one that made me feel my understanding of Boolean Algebra was shaky:
X = (AB' + C')EG + (KF + HA)I'
I'm only interested in the following part at the moment:
AB'
Given:
2 input AND gate = AB
2 input NAND gate = (AB)'
2 input OR gate = A+B
2 input NOR gate = (A+B)'
AA = A
A'A' = A'
De Morgan's Theorem:
(A+B)' = A'B'
(AB)' = A'+B'
I drew this as the equivalent of an AND gate:
Then I drew this for AB', but my gut says something is wrong:
Is it correct?
Nomnom,
k00k1e