# Nodal Analysis

Discussion in 'Homework Help' started by p75213, Aug 1, 2011.

1. ### p75213 Thread Starter Member

May 24, 2011
39
0
The answer is 20V but I am having problems figuring out how it is derived. I think there is a supernode in there but the voltage sources in parallel have got me confused.

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2. ### blah2222 Well-Known Member

May 3, 2010
565
33
KCL(Vo):

$\frac{Vo - 30}{2k} + \frac{Vo - 20}{5k} + \frac{Vo}{4k} = 0$

$Vo(\frac{1}{2} + \frac{1}{5} + \frac{1}{4}) = 19$

$Vo(\frac{20 + 8 + 10}{40}) = 19$

$Vo(\frac{38}{40}) = 19$

$Vo = 20$

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