Night Light with white LED's

Thread Starter

mkbutan

Joined Sep 30, 2008
299
hi
I would like to make one night light with 8-12 white LED's for reading the book's at bed time
which should turn on when power is on and should turn off one by one (as rechargeable battery (1.2V 2100mAh * 4) ) go's weak it should run for about 1 or 1 1/2
(may be some thing like Battery Tester , which shows the strength of the battery)
pl help
Should I use decade counter or the op-amp to design the ckt or something else
I don't want to use the timer in the ckt.
 

wayneh

Joined Sep 9, 2010
17,498
I don't want to use the timer in the ckt.
Why? It would be an easy way to generate a clock pulse, which you'll need from something.

Just to be restate your goal - you want 8-12 LEDs to turn on with the power switch, but then have one go out every 5-10 minutes? Reset on power switch off.

First off, in my experience, you only need 3-4 LEDs for plenty of light. The commercial reading lights are like that. I have a newer one that uses only 1 very bright LED.

Secondly, I'm wondering how this would work. If you start reading with 10 LEDs, how will it look when only 1 is lit? It'll get harder and harder to read, I think.

I like the idea of having the impartial timer enforce bedtime lights off.
 

Thread Starter

mkbutan

Joined Sep 30, 2008
299
First off, in my experience, you only need 3-4 LEDs for plenty of light. The commercial reading lights are like that. I have a newer one that uses only 1 very bright LED.
OK 3-5 LED's will also work for me but not that 1 very Bright LED (it hurts)
the reason i go to sleep while reading the book

can i use the capacitor as a timer
as the current in the capacitor discharge the led's go's off

any help
sos
sos
sos
 
Last edited by a moderator:

Austin Clark

Joined Dec 28, 2011
412
OK 3-5 LED's will also work for me but not that 1 very Bright LED (it hurts)
the reason i go to sleep while reading the book

can i use the capacitor as a timer
as the current in the capacitor discharge the led's go's off

any help
sos
sos
sos
Good luck getting a capacitor that will work that way.
You could maybe use an analog to digital converter to turn off the LEDs as the battery voltage gets too low.
 

wayneh

Joined Sep 9, 2010
17,498
Good luck getting a capacitor that will work that way.
What Austin means is, a capacitor able to do this job would be quite large, even if you use a circuit to only monitor its voltage as that voltage slowly decays. (It won't work at all to use a capacitor to power your lights). If you have to buy a big capacitor, you won't like the price. If you can find one in an old audio amp, TV or such, you might be able to do it. Without doing the math, I'd guess you'll need at least about 2,000µF to have a chance. More is better.

To do the math properly, you'll need to know how much current will flow through your voltage detector. The capacitor will have to supply that current throughout the working time of your circuit.

Another problem with the capacitor voltage decay is that it's logarithmic, not linear. If you trigger of a ∆V of say 0.5V, the first ∆V will be much faster than each succeeding interval. The LM3914, or maybe a similar chip, might be able to compensate for that by looking for successively smaller ∆Vs.
 

absf

Joined Dec 29, 2010
1,968
The LM3914 suggested by Mr Chips would fulfill all of your requirements. Very good choice. Study the datasheet attached.

Allen
 

Attachments

wayneh

Joined Sep 9, 2010
17,498
The similar LM3915 compensates for a logarithmic decay instead of linear, if the OP wants to use a capacitor as a timer.

The datasheet suggests the input current is no more than 0.1µA. So the capacitor might have to supply as much as 0.1µAh to operate as a timer for an hour. 0.1µAh = 360µAs At 3V average, this is only 120µF. So a modest cap of 1000µF could be used in an RC timer with the IC itself drawing only a fraction.
 

Wendy

Joined Mar 24, 2008
23,429
A SMPS current regulator will suck a battery dry before the LED dies, and will maintain constant light throughout. Problem is, it is not very good for the battery to be fully depleted.
 

Thread Starter

mkbutan

Joined Sep 30, 2008
299
Use an LM3914.


thanks
but ti data sheet says :-

The LM3914 is very easy to apply as an analog meter circuit.
A 1.2V full-scale meter requires only 1 resistor and a single
3V to 15V supply in addition to the 10 display LEDs. If the 1
resistor is a pot, it becomes the LED brightness control. The
simplified block diagram illustrates this extremely simple
external circuitry

Question is whether the 1.2*4=4.8 v/2100mA/h battery
(Kodak Rechargeable Digital Camera Battery Ni-MH AA HR6 2100mAh 1.2V)
with 5-10 LED's will glow sufficiently for reading the book in dark?
 

Wendy

Joined Mar 24, 2008
23,429
One LED is enough to read a book in the dark, if it is a book light and next to the book. It sounds to me you are wanting a reading light for a room, basically a desk lamp. Since LEDs tend to be directional, it should be fine. Are you wanting to deplete the battery completely, or put it on a timer to preserve battery life? How portable are the batteries going to be?
 

Thread Starter

mkbutan

Joined Sep 30, 2008
299
yes i want the reading light which should run only for an hour or one and a half (60-90 Min.)
There are 4 AA battery's
1.2*4=4.8 v/2100mA/h battery
(Kodak Rechargeable Digital Camera Battery Ni-MH AA HR6 2100mAh 1.2V)
 

wayneh

Joined Sep 9, 2010
17,498
Those batteries will provide hours and hours of operation with even 5 LEDs.

Each LED uses about 15mA at 3v, or about 45mWh for each hour of operation. Each battery delivers 2100mAH at 1.2V or 2,520mWh. There will be losses due to circuitry and/or or current-limiting resistors, but still plenty of power.
 

absf

Joined Dec 29, 2010
1,968
I simulated the circuit with 5 LED with proteus. When battery is 4.8V, all 5 are lighted but only 4 are lighted when the battery voltage drops to 4V. The current is almost as expected by wayneh ie 15mA per LED, but the consumption per LED drops when more LED are lighted (see circuit attached).

I have not yet studied how to add the delay for 1 to 1.5 hours but I think it shouldnt be too hard.

Allen
 

Attachments

wayneh

Joined Sep 9, 2010
17,498
If you insist on using the battery itself as the clock, I wonder if you couldn't use a single AA with a joule-thief circuit. This would drop the battery voltage much faster.
 

#12

Joined Nov 30, 2010
18,224
If the joule theif lasts too long, you can add a load resistor to make the battery fail sooner or use a AAA battery or maybe even a "button" battery.
 
Top