- Joined Apr 15, 2011
But the negative-OR which is nothing more than a NAND gate, we have a special case. When both inputs are LOW we get HIGH output, and when both inputs are HIGH we get LOW output. This is what differentiates a normal OR gate from a negative-OR gate.
This makes no sense to me."Even if it's raining OR there is a cyclone, I would still go to see Sally at the airport".
I don't really get it. Negative OR logic cannot be implemented using normal OR gate which is used for implementation positive OR logic. When a NAND gate is used to implement negative OR logic, it is given a special symbol. But it's still very much a NAND gate. I think it's only a matter of interpretation. Isn't it?Not quite right.
A negative-OR as shown in post #2 must not be considered as a NAND gate (even though it may be implemented with a 7400 NAND gate).
A negative-OR as shown in post #2 is an OR gate with ACTIVE-LOW inputs
The output is TRUE (HIGH) if either input is ACTIVE-LOW.
So your statement should read:
"When EITHER input is LOW we get HIGH output"
The equivalent statement for a positive logic OR gate would be:
"When EITHER input is HIGH we get HIGH output"
I was trying to use negative OR logic.This makes no sense to me.
What your logic tells me is if it is not raining and there is no cyclone, Sally is stuck at the airport without you.
What you have to determine firstly is, is it an AND condition or an OR condition you want to convey?
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