Needed Formula

Thread Starter

KCHARROIS

Joined Jun 29, 2012
311
Hello

I'm in need of a formula that to convert a j value to an inductance or capacitance value.

Example: How does j126Ω at 100 MHz equal 200nH

Thanks
 

MrChips

Joined Oct 2, 2009
30,714
Z = jωL = j2πfL

R = 2πfL

L = R/(2πf)

R = 126Ω
π = 3.1416
f = 100MHz

For capacitance:

Z = j/(ωC) = j/(2πfC)
 
Last edited:

Papabravo

Joined Feb 24, 2006
21,159
Simple algebra.

If
XL = ωL, then L = XL / ω, which also equals XL / (2πf)

So:

126 / (2 * 3.1415926 * 100E6) = 200E-9 = 200 nH
 
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