Need help simplifying a circuit and finding power

Discussion in 'Homework Help' started by sheltered, Jan 28, 2010.

  1. sheltered

    Thread Starter New Member

    Jan 28, 2010

    I know this may be a silly question, but I have a circuit problem for homework and I can't figure it out. It requires you to find the power for each resister and each source.

    Please explain!

  2. t_n_k

    AAC Fanatic!

    Mar 6, 2009
    You know how much current flows in the 1Ω and the 3Ω. Power in each is then easily found.

    The total current into the top of the centre parallel branch network is
    6A-2A=4 A.

    Use current divider rule (say) to work out how the current splits in each leg of the parallel network. You can then find the power in the other resistors.

    Work out the voltage drop across each current source - then the power delivered by each source will subsequently be found.

    Hopefully power from sources = total power dissipated in resistors