Hello
There are 3 inputs x,y,z and three outputs A,B,C
when the binary input is 0,1,2,3, output is one grater than the input
when the binary input is 4,5,6,7, output is one less than the input.
I came up with this truth table but i don't know whether this is the correct way or not
x y z A B C
0 0 0 0 0 1
0 0 1 0 1 0
0 1 0 0 1 1
0 1 1 1 0 0
1 0 0 0 1 1
1 0 1 1 0 0
1 1 0 1 0 1
1 1 1 1 1 0
according to this
A=xy+yz+xz
B=x'y'z+x'yz+xy'z+xyz
C=z'
any reply would be greatly appreciated
thanks
cat
There are 3 inputs x,y,z and three outputs A,B,C
when the binary input is 0,1,2,3, output is one grater than the input
when the binary input is 4,5,6,7, output is one less than the input.
I came up with this truth table but i don't know whether this is the correct way or not
x y z A B C
0 0 0 0 0 1
0 0 1 0 1 0
0 1 0 0 1 1
0 1 1 1 0 0
1 0 0 0 1 1
1 0 1 1 0 0
1 1 0 1 0 1
1 1 1 1 1 0
according to this
A=xy+yz+xz
B=x'y'z+x'yz+xy'z+xyz
C=z'
any reply would be greatly appreciated
thanks
cat