OK, the amount of error will be pretty small then.Thanks for the replies!
The input impedance is about 5.2 ∼ 7.8 Ω, and the output is just a sensor that reads the output voltage...
The bypass capacitor across the opamp's power pins is mandatory.I don't think that the bypass capacitor is necessary, as the input comes from a DC circuit...
I don't know where you got the idea that the OP was working on an oxygen sensor for a hydroxy project, as the numbers would be all wrong for something like that.question? when you say when in1 is 0 you need .5 volts and 9.5 volts in1 for 3.9 volts, is that when and only when the input reads these values do you get what you ask at the output? You also state that you need other values from 0-5 volts and from 0- 3.9 volts If I am following you. Or did you mean 0-.5 volts? and 0-3.9 volts? It appears you are asking for three things to happen. I did see Sgt's drawing. You say the output is just a sensor that reads voltage? I am assuming because the lack of data that the sensor needs to read or see the .5 volts if 0 volts. And if the input rises to to 9.5 volts to not go over 3.9 volts, and so anywhere in-between would be acceptable? Sounds to me like you are working on emulating an oxygen sensor for a hydroxy project. Am I right?
If for some reason the input goes over 9.5 volts Sgt's diagram would result in 4.3 volts at the output. If you use his diagram which is ingenious and great thinking on his part, as for me it hurts to think anymore, not saying I could of thought up that anyway, but I would place a zener diode at the output to hold it at 3.9 volts should it go over, or other precision device. The thing that puzzles me is that you say 0 volts should be .5 volts yet as it breaks away from 0 volts and starts to rise then what should it be? or is it anything below .5 volts is considered zero, meaning is your device's low end .5 volts and if the voltage drop off lower than .5 volts its still .5 volts? Ive confused myself and everybody else now. Look I am just trying help too in case the diagram is not what you are looking for, as there are many ways to get the the end result.
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by Steve Arar
by Jake Hertz