thanks broUse Thévenin to create an equivalent schematic at the base of the transistor.
Now you can find Ib ==> Vb = -Ib*Rb -0.7 -Ie*Re with Ie=Ib(beta+1)
Go back the orignal schematic and now you know what current is flowing out of the base.
Vcc = (I2+Ib)*R1+I2*R2 ==> Find I2
I1 = I2+Ib
Mind the signs.
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