http://postimg.org/image/74ghsdpul/Seems simple enough. I think textbook should have example or two on how to solve this type of problem.
thanks broUse Thévenin to create an equivalent schematic at the base of the transistor.
Rb= R1//R2
Vb= (Vcc*R2)/(R1+R2)
Now you can find Ib ==> Vb = -Ib*Rb -0.7 -Ie*Re with Ie=Ib(beta+1)
Ib= -(Vb+0.7)/(Re(beta+1)+Rb)
Go back the orignal schematic and now you know what current is flowing out of the base.
Vcc = (I2+Ib)*R1+I2*R2 ==> Find I2
I1 = I2+Ib
Mind the signs.
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