Does it mean for example: when the op amp is connected to +5 and -5V that I don't need biasing. But when the op amp is connected to +5V and ground I need biasing. Because sometimes I see op-amps that is connected to +5V and -5V is still biased by using resistors of equal resistances in voltage divider setup. For example the circuit attached. why?An op amp can not produce signals outside its power rails, so if it is only powered by a single ended supply, that is from 0V to a positive voltage, you need to bias (or shift) the signal up to a center point between the two supply voltages. Other op amp circuits are powered by a split supply, that is a supply that has three wires and give -V 0V and +V. This can have it's signal biased at zero volts as the output can swing either side of zero.
Can someone explain to me in a simple way what is dc biasing (is it same as bias voltage?), dc offset and dc coupling.
Biasing is almost always required, but in some cases the common or ground line or some convenient supply rail happens to supply the appropriate voltage. If the required voltage does not exist, it must be provided somehow, and a pair of resistors connected as a potential divider s often used to do this....Does it mean for example: when the op amp is connected to +5 and -5V that I don't need biasing. But when the op amp is connected to +5V and ground I need biasing. Because sometimes I see op-amps that is connected to +5V and -5V is still biased by using resistors of equal resistances in voltage divider setup. For example the circuit attached. why?
As shown, the circuit will be biased to +2.5V. This seems unusual given that V+ and V- supplies are provided.In regard to the previous attached circuit. It has +ve and -ve voltage but still biased, so is it correct? My other question is when bias by 2.5V what could be the amplitude of the signal if a signal of 5 V amplitude is applied to the input (is it going to be 7.5V)? Also is my understanding of biasing correct based on the previous attachment.
Depending on the amplifier used, the +5V and -5V supplies may be required to obtain enough total supply voltage.Here is the complete circuit and the explanation given with it. I found it in the internet. Its a circuit for digital guitar tuner. So, can you tell me whether biasing was necessary even though the circuit uses +5V and -5V.
Is dc biasing and dc offset the same thing? From my understand after reading these explanation it seems the same.
When an AC signal with 10Vpp biased at 2.5 V means, now the AC signal has +7.5V and -2.5V. So dc biasing means you make a point for the AC signal to oscillate instead of normal 0.
Note that you cannot expect to get any voltage outside the range of voltages supplied to an amplifier, and in some amplifiers can only produce significantly smaller output voltages than their supply rails.My microcontroller has an ADC of 5V (0 to 5V). The input signal is 25 mVpp. And I want to amplify it to 5V.
1) So I need an amplification of 200. (gain = 5000/25), right?
2) I need the amplification circuit to be powered by battery and should be portable. So, should I use single supply or dual supply using battery?
3) If I am using single supply, at which voltage should my biasing be and what should my +Vcc be? (I need output 5 Vpp, when the input is 25 mVpp)
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by Jake Hertz
by Jake Hertz
by Jake Hertz