Also Let's just say this is a 2 ft long wire capable of huge Amperage connected between the 2 ends of a battery (again capable of whatever the circuit needs)

For example, you have a wire that is 2 feet long and the time for the signal to start at point A and reach B is 2-nanoseconds because information can't travel faster then light and each foot at light-speed is about 2-nanosecond.

A X----------------------------------------------X B

Now is it possible to shorten the time needed for the signal to reach point B by just adding another wire to the circuit in the middle. So now the time needed between each point is 1ft = 1-nanosecond.

A X--------------------------B X ----------------------X C (old B)

But since the signal we are sending is basically just a on signal. Then wouldn't the time needed to power up this wire be half what it would before?

Also let's say A and B are at 12v (doesn't really matter what it is) and C is 0V or Ground.

So wouldn't the current start flowing between A and B while also start flowing Between B and C even though A and B are at the same Voltage. If you think about it and the timescales involved then I would think so. Since the current flow at B is just as much as at A, then when they meet it would be as if there was no B and there was just A and C. But the time needed for the current to rise would be half what it used to be? sound right?

I think it makes since if you think about the way it works.

1.Voltage applied at point A and B

2. current starts moving from Point A toward B

3. at the same time the current from Point B moves both toward A and C

4. Voltage reaches B and C and voltage from B reaches both A and C

This is where I get a little confused, the current flowing between A and B are moving towards each-other (Current from B is also moving toward C but that is the correct direction.) What happens when the current from B reaches A, does the current just change direction back towards B. If so how does this effect the total turn-ON time for the wire.

Could I just put a diode in-between A and B to stop this, obviously as close to B as possible though , lol.