Hi. I was working on this problem and could use some help. I have to calculate the power dissipated. My thinking was to find the drain current and then multiply it by the drain voltage to get power but thats not right.
WHAT I DID:
Vdd-Vd = V = 5 - 0.9 = 4.1 V
V/R = I = 4.1V/1.6E3 = .00256 A (drain current)
P = I^2R = (.00256)^2*1.6E3 = .0105 W
The inverter circuit above consists of MOSFET and the load resistor, R = 1.6 kOhm. The inverter bias voltage is Vdd = 5 V; the MOSFET threshold voltage is 0.5 V. The gate input voltage is +5V. Under these conditions, the MOSFET drain voltage is Vd = 0.9 V; Assuming that the MOSFET I-Vs are linear at this drain voltage, find the power (in Watts) dissipated in the inverter circuit.
WHAT I DID:
Vdd-Vd = V = 5 - 0.9 = 4.1 V
V/R = I = 4.1V/1.6E3 = .00256 A (drain current)
P = I^2R = (.00256)^2*1.6E3 = .0105 W
The inverter circuit above consists of MOSFET and the load resistor, R = 1.6 kOhm. The inverter bias voltage is Vdd = 5 V; the MOSFET threshold voltage is 0.5 V. The gate input voltage is +5V. Under these conditions, the MOSFET drain voltage is Vd = 0.9 V; Assuming that the MOSFET I-Vs are linear at this drain voltage, find the power (in Watts) dissipated in the inverter circuit.