circuit shown below. Our aim in this problem is to determine the open circuit voltage voc at the terminals A and B by utilizing the mesh current method.

I drew the mesh currents in the appropriate windows but cannot get the right answer when I start writing my KVL's.

From the diagram, I said 1.2Vx = i3-i2.

I also wrote a super mesh equation that combined the windows of i2 and i3. Starting from the node directly under the current source

1ohm(i2-i1) - (i2)0.5ohm - i3(0.625ohm) = 0

working out the algebra yields

0.5i2 - 0.625i3=i1

Then I calculated the loop of i1 starting from ground

20 -(0.5i2 - 0.825i3)1 - 1(i2-(0.5i2 - 0.625i3) = 0

This gave i2 = 20A

Looking at the diagram, you can see that Vx = i2*0.5ohms. I substituted this into the equation 1.2Vx = i3-i2.

Rewriting gives 1.2(i2*0.5ohms)+i2 = i3 or 1.6i2 = i3

so i3 = 1.6(20) = 32A

I think I wrote the correct equations but the math just doesn't add up. Voc is 5V and in order for it to be 5V, i3 has to be 8A...