# Mesh Current Analysis for an RLC Circuit - Help!

Discussion in 'Homework Help' started by mdb, Feb 11, 2011.

1. ### mdb Thread Starter New Member

Feb 11, 2011
3
0
Hello,

The assignment says find the magnitude and phase of V0 using mesh current analysis. I simulated the circuit and found the value of V0 to be 7.591 <72.0° V. However, I wasn't able to solve using mesh current method because of the current source in the middle.

The circuit diagram is attached. Any help is greatly appreciated. Thanks.

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2. ### lezahyoj New Member

Feb 7, 2011
11
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For two meshes containing the same current source take a path around the outside of the two meshes avoiding the current source - this is called a super mesh.

3. ### mdb Thread Starter New Member

Feb 11, 2011
3
0
Thank you so much. Here is what I have so far. The final answer is different from what I had in PSPICE! Can someone please confirm my solution?

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4. ### The Electrician AAC Fanatic!

Oct 9, 2007
2,630
468
I get Ic = 8.538 + j3.081

I think you have a wrong sign for the (1,4) element of your matrix.

5. ### mdb Thread Starter New Member

Feb 11, 2011
3
0
Thanks alot! I made the correction and got the same number Ic = 8.538 + j3.081.

Last edited: Feb 12, 2011
6. ### lezahyoj New Member

Feb 7, 2011
11
0
but that wasn't the same as the result of your PSPICE right?
I know a different procedure from yours.

you obtained an equation IC-IB=12, from that you will get IB=IC-12. Try to substitute this equation from the other equation you get from the loops then omit the [0 -1 1 0 12] from the matrix.

I'm not quite sure if this will work but there's no harm in trying (if no high voltage is involved)