http://img140.imageshack.us/img140/3572/scan0028.jpg
a) the only proof I can come up with is that for RS = 0, RL would have max power put into it because there would be no voltage drop across RS since it doesn't exist, so since p=vi, the max power (source) would be going into RL.
b) I'm not sure
c) I'm not sure
Doing some analysis on the circuit I know that:
VL = Vi*(RL/RS+RL)
VS = Vi*(RS/RS+RL)
I = Vi/(RS+RL)
We did this problem before.. you have to get a function of something and take the derivative to maximize the function...
a) the only proof I can come up with is that for RS = 0, RL would have max power put into it because there would be no voltage drop across RS since it doesn't exist, so since p=vi, the max power (source) would be going into RL.
b) I'm not sure
c) I'm not sure
Doing some analysis on the circuit I know that:
VL = Vi*(RL/RS+RL)
VS = Vi*(RS/RS+RL)
I = Vi/(RS+RL)
We did this problem before.. you have to get a function of something and take the derivative to maximize the function...