# Mathematical Poetry

Discussion in 'Math' started by Thevenin's Planet, Apr 13, 2010.

1. ### Thevenin's Planet Thread Starter Active Member

Nov 14, 2008
183
2
How de again!

What's up or down with the poetry in the Math section? a meter is the measured arrangement of words in poetry, as by accentual rhyth, syllabic quantity, or number of syllables in a line. Or a particular arrangement of words in poetry,such iambic pentameter,determined by the kind and number of metrical units in a line. This is Math not poetry.

2. ### Clay Member

Feb 12, 2010
21
8
There was a young fellow named Fisk,
Who's fencing was exceedingly brisk,
So fast was his action,
The Fitzgerald Contraction,
Reduced his rapier to a disk.

(George Gamow, 1,2,3 infinity)

Best regards,

/Clay

3. ### Thevenin's Planet Thread Starter Active Member

Nov 14, 2008
183
2
Good Day

When one learns about math poetry one can attemp to simplfy this poem.The transform function mybe needed.

Der Shmied

Am schwarzen Kamin
Da sitzet mein lieber
Doch geh'lch voruber
Die Balge dann Sausen
Die flammen Aufbrausen Und loden um ihn.

4. ### Thevenin's Planet Thread Starter Active Member

Nov 14, 2008
183
2
I need someone to check this out for me.I been working on these complex
number for some time.I am using the rectangular function.I use the congugate method also to remove the J in the denominator.
All the capacitors are 0.1 microfarad, and all the resistors are 200k,at a frquency of 3.2 hertz. A RC lead network.

z5=200k-j497359.2 ; Z4,5=200k-j497359.2/(200k-497359.2)(0j497359.2)
Z4,5=(-9.95^10-j2.5^11/200k-j99477.4)*0+j994718.4(conjugate).
Z4,5=-9.897^11-j2.486^17/1^11
Z4,5=9.897-j248700.0 =248700.0 @-89.99 degrees
Z345=(9.897-j248700)+(-j497359.2)
parellel
Z2,3,4,5=(9.897-j746059.2)(200k-j0)/9.897-j746059.2)+(200k-j0
Z2,3,4,5=(1979400-j1.5^11/200009.9-j74606 )*(200009.9+j74606/200009.9+j74606
Z2,3,4,5=1.12004^16-j3^16/4.557^10=245805.8-j658384.844=702773.9 @-69.5 degrees
Z1 in series withZ2,3,4,5.
Z1,2,3,4,5=(245805.8-j658384.844)+(0-j497359.2=245805.8-j708124.041=749573.311 @-70.85 degrees.
I was aspecting zero if all these calculation is correct.Did something happened wrong?

Last edited: Apr 15, 2010
5. ### retched AAC Fanatic!

Dec 5, 2009
5,201
315
If you multiply the result by 0(zero) to the end, you will get zero.

6. ### Thevenin's Planet Thread Starter Active Member

Nov 14, 2008
183
2
I places zeroes in to keep up with the counting sequences.From sometime i would get zeroes confuse with addition,division ect.That's good reminder.

7. ### Thevenin's Planet Thread Starter Active Member

Nov 14, 2008
183
2
I not sure if I understand what your are refering to,the -99.5 raise to 10 power. It comes from multiplying 200k by the capacitor which is -j497359.2. Since Z1 is a capacitor,C1 in series with a R1, resistor. Z2 is in parallel to Z1,which is a R2,200k,.And Z3 is C2 in series to Z1 and Z2.The third Resistor,R3 is parallel toZ1,Z2,and Z3 and is 200k.C3 is the last capacitor and is the input to the lead circuit and has the same Xc.All resistors leads to ground indicating there position are in parallel.They wll charge up or a max voltage will be across them before the capacitor become fully charge.That is the voltage across the resistor will lead the voltage across the capacitor(s). I calculated from the output toward the back toward the input. What is the problem with my calculation? Multipling the 9 and adding the single digits has no rythm to me. The number 9 just happen to get there from calculations. Or is the a quick method of addinf poers of ten ?

Last edited: Apr 16, 2010