Hello everyone,

I have figured out the amount of current it takes, it functions like this:

= 12/2(1 - e^-4/3.5)

=6( 1 - e^-1.1428)

4.0866 = 6 ( 0.6811)

Cant figure out the seconds because i'm not sure how to find -t of logs:

So setup the second equation we have

5 = 12/2( 1 - e^-t/3.5)

Thanks

 

hi,
This link should help for Ln < > e conversions

http://www.rapidtables.com/math/algebra/Ln.htm