I have spent numerous hours recently researching ways to wire LED's so far for a home project I am working on which involves wiring:
33 red
38 blue
471 white LED's.
Unfortunately there I no scope for reducing the number of LED's so that is has to stay the same. I kinda knew I would end up hAving to seek your professional help on the matter eventually as nothing would elucidate an answer so to avoid asking silly or obvious questions I have worked out that:
The red circuit will require:
1454mW
120mA
Blue:
3208mW
260mA
White:
38,622mW
3140mA
With total requirements from the source being:
3.52A
43.28W
Please see the incredibly crude diagram of how I'm planning on putting the strings together.
The reason why After my research i have decided to wire it like this is because I've been told with very long strings in parallel, it will incur a voltage drop from one end to the other.
Now for the questions:
The driver that I have been looking at is a 45W driver with a 4A output - With the shorter red and blue strings (all circuits to be connected in series and paralell) being attached straight to the power supply will the high power output cause an issue with it? I read somewhere that the power rating of a driver merely what it can HANDLE as opposed to what the actual output and I guess according to ohms law the power is generated in the circuit not given out.
Secondly with having all the strings connected in a 'spider circuit' formation, does this mean that each string will get the full 4A of current thus will need resistors to bring it back down to size or is it true that the individual circuits will conduct only what they need?
Thirdly which is more of an extension of the first, because the power rating of the driver is 1.72W over what the circuit requires, will this require some additional resistors before unleashing it to the mercy of the LED's?
Fourthly - is 157 LED's per string connected in 52 separate sub branches of series far too many so the LED's at the start will be brighter than those at the end?
Please forgive me if my nomenclature isn't up to par - electronics is not. Something I have ever studied before and I have made a concerted effort to try and not waste your time!
Kindest regards
Gorton
33 red
38 blue
471 white LED's.
Unfortunately there I no scope for reducing the number of LED's so that is has to stay the same. I kinda knew I would end up hAving to seek your professional help on the matter eventually as nothing would elucidate an answer so to avoid asking silly or obvious questions I have worked out that:
The red circuit will require:
1454mW
120mA
Blue:
3208mW
260mA
White:
38,622mW
3140mA
With total requirements from the source being:
3.52A
43.28W
Please see the incredibly crude diagram of how I'm planning on putting the strings together.
The reason why After my research i have decided to wire it like this is because I've been told with very long strings in parallel, it will incur a voltage drop from one end to the other.
Now for the questions:
The driver that I have been looking at is a 45W driver with a 4A output - With the shorter red and blue strings (all circuits to be connected in series and paralell) being attached straight to the power supply will the high power output cause an issue with it? I read somewhere that the power rating of a driver merely what it can HANDLE as opposed to what the actual output and I guess according to ohms law the power is generated in the circuit not given out.
Secondly with having all the strings connected in a 'spider circuit' formation, does this mean that each string will get the full 4A of current thus will need resistors to bring it back down to size or is it true that the individual circuits will conduct only what they need?
Thirdly which is more of an extension of the first, because the power rating of the driver is 1.72W over what the circuit requires, will this require some additional resistors before unleashing it to the mercy of the LED's?
Fourthly - is 157 LED's per string connected in 52 separate sub branches of series far too many so the LED's at the start will be brighter than those at the end?
Please forgive me if my nomenclature isn't up to par - electronics is not. Something I have ever studied before and I have made a concerted effort to try and not waste your time!
Kindest regards
Gorton
Attachments
-
161.4 KB Views: 105