im struggling with kirchoffs law and find it hard to understand. i got two supplys in parallel,8v and 10v.on the negative side of the 8v supply there is a 4Ω resistor, on the negative side of the 10v supply there is a 6Ω resistor, the branch between the two supplys on the positive side is a 1Ω resistor and to the right hand side of the 10V supply is a leg of its own with a 10Ω resistor with no supply, so far ive for 8= and 10= LOL

 

can you post an image of the circuit it would be easier to understand

 

il try and explain it abit better so you can draw it.imagine a 3 leg parrallel network but so each leg is VERTICAL.In the middle leg theres a 10v supply,underneath the supply is a 6Ω resistor. on the left leg theres an 8v supply,underneath the supply is a 4Ω resistor.the 3rd leg on the right has a 10Ω resistor only. The branch on the positive side of the two supplys has a 1Ω resistor

 

is this correct

 

Assuming circuit is ok. Is the working below correct anyone ?