Through Kirchhoffs voltage laws Ive found

Current in Loop one (I1): 3 Amps going anticlockwise

Current in Loop Two (I2): 4 amps going anticlockwise

Current in Loop Three (I3): 8 amps going anticlockwise

R1: 5 amps going up = (Current in loop three - current in loop one) -5amps going down = (current in loop one - current in loop three)

R2: 3 amps going up -3 amps going down

R3: 4 amps going up = (Current in loop three - current in loop two) -4 amps going down = (current in loop two - current in loop three)

R4: 4 amps going up -4 amps going down

R5 -1 amps left to right = (current in loop one - current in loop two) 1 amps right to left = (current in loop two - current in loop one)

All these currents are going anticlockwise but the problem they've given me has 8 amps written on it going clockwise.

So when I apply Kirchhoffs Current Laws (The sum of currents going into a node plus the currents going out of a node = 0) starting with the 8amps clockwise they've given me I find the opposite to what I've found when I solved the voltage laws.

Specifically using the current laws starting with 8amps clockwise I now have:

R1: 5 amps going down the resistor

R2: 3 Amps going down the Resistor

R3: 4 Amps going down the resistor

R4: 4 Amps going down the Resistor

R5: 1 Amps going left to right

Am I right in saying that By using Kirchoffs voltage laws Ive found the electron flow. The direction the electrons flow from the negative of the battery to the positive.

But if I use kirchoffs current laws and start with the "8 Amps clockwise" the lecturer has given me in the problem Im now actually finding the direction of the conventional flow?

Which is why it's directly opposite to the electron flow I've found when I used Kirchhoffs voltage laws?

many thanks if you could clear this up