# Karnaugh Maps, Boolean Expressions etc.

Thread Starter

#### Nitrag

Joined Sep 16, 2007
8
Hi all, first time poster..Anywho have a couple questions about my hw.

How do you convert a Boolean Expression to a karnaugh map? I first had to draw the circuit using the boolean expression. now it wants me to draw a karnaugh map. How do I go about doing this? Do I use DeMorgan's?

Rich (BB code):
f(a,b,c)=(a+c)(b'+c)(a'+b)

Thread Starter

#### Nitrag

Joined Sep 16, 2007
8
I read both but it's still not clicking. The function isn't in a form that I can translate from boolean to k-map.

Is there a way to get it to a'b'c+c'b'a form? I don't know how to work with (a+b)