Hi guys,

Just to check, is there any exam papers i could find on the net provided with solutions as my digital logic exam is just round the corner. Would appreciate greatly any material or exam papers. I am a Year 1 CS student anyway.

 

Read through This

It will help you a lot. Especially since it is FREE too!

 

Hello,

If you want to test your knowledge of the digital circuits, you could take a look at the digital circuits section of the worksheets:
http://www.allaboutcircuits.com/worksheets/index.html

Bertus

 

Hey bertus, thanks for the link but they are apparently too hard for me to understand. I am only a Year 1 student so the course i am undergoing is relatively introductory so do you have any other links which are relatively less complicated. To be honest, i couldnt even understand the questions or the answers in the worksheet.

 

Hey bertus, thanks for the link but they are apparently too hard for me to understand. I am only a Year 1 student so the course i am undergoing is relatively introductory so do you have any other links which are relatively less complicated. To be honest, i couldnt even understand the questions or the answers in the worksheet.

Everything in the worksheet and quiz is covered in the link I posted.

 

Well i have a question which goes like this:

Given an Equation :
F = A'B'CD' + B'C'D + A'B'C' + AB'D
use a 4x1 multiplexer with an enable input plus other gates
draw out the circuit based on this equation. Anyway the enable is active-low.

I do have the answer but i cannot seem to understand why do they use A and C inputs as the select bits whereas the D inputs are belonging to the 4 x 1 multiplexer with one input being constant. Could some1 kindly please explain to me.

 

Skip to Here and draw out the truth table for the expression.

From there, look at the behavior of a 4-1 multiplexer with enable.

The ' as in A' means NOT A, and AB means A AND B, A+B is A OR B, and A'B is NOT A AND B

It's just a system of notation for text discussion of logic.

 

Have a read in these links and come back with your questions:
http://forum.allaboutcircuits.com/showthread.php?t=55121
http://forum.allaboutcircuits.com/showthread.php?p=367021
http://forum.allaboutcircuits.com/showthread.php?t=53799

 

Hi. Thanks a lot guys! I think i figured my question and answer out. You guys are a great help!