In theory, your calculation is correct. You would have to put the ammeter in series with the load - not across the battery. But I wouldn't advise trying it with no load. The resulting flash as you made the connection wouldn't do your eyes - or your nerves - much good!Originally posted by frisky@Aug 15 2005, 08:26 PM
If a voltmeter and an ammeter were connected across a 12 V battery with an internal resistance of .02 ohm, would you just use ohm's law to calculate the expected output of the battery?
volts out = 12; current = 12/.02 = 600 amp ?
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