internal resistance

Discussion in 'Homework Help' started by frisky, Aug 15, 2005.

  1. frisky

    Thread Starter New Member

    Jul 25, 2005
    If a voltmeter and an ammeter were connected across a 12 V battery with an internal resistance of .02 ohm, would you just use ohm's law to calculate the expected output of the battery?

    volts out = 12; current = 12/.02 = 600 amp ?
  2. pebe

    AAC Fanatic!

    Oct 11, 2004
    In theory, your calculation is correct. You would have to put the ammeter in series with the load - not across the battery. But I wouldn't advise trying it with no load. The resulting flash as you made the connection wouldn't do your eyes - or your nerves - much good!