intel memory addressing(effective address or offset) in 16 bit protected or real mode

Intel-desktop processors like core to quad, i7....

My question is how we can write effective address in 16, 32 or 64 bit modes. We know that the following is a valid effective address in 16 bit IA-32 protected:
[BX+SI]+disp8
Can we specify: [BH+SI]+disp8 as an address?

Also suppose we write a code for IA-32 protected, the following is a valid effective address:
[EAX]+disp32

But is , [AX]+disp32 a valid valid effective address? how about [AL]+disp32?

In real mode(16-bit) we have [BX]+disp8 but is "[BL]+disp8" valid?

And my last question is that how you write a valid address in 64 bit mode?

 

Are you just asking generally or are you using a specific compiler and or a specific task at hand?

For instance:

In which compiler?

 

For the 80286 and 80386, [BX+SI+disp8] is valid. [BH+SI+disp8] is not.
As far as I know, no x86 processors support 8 bit registers as part of
the effective address.

Again, the address [AL+disp32] contains an 8 bit register and is not valid
on the 80386. [EAX+disp32] on the other hand, is supported by the 80386.
[AX+disp32] is not valid on the 80386.

I'm not familiar with the 64 bit mode of newer processors.
[BL+disp8] contains an 8 bit register and is not a valid effective address on
the 80286 or 80386.

 

it seems that effective address is considered by some specific registers in different code segments. Like in 32 bits, [EAX] is valid and instruction format is decoded by using EAX and no format exists for AX.

in 64 , default is 32 and we can use EAX, EBX,... but with REX.w=1, we can use [RAX], i mean CPU considers RAX when decoding the instruction.

If i am wrong please let me know. Thank you.