guys how do u calculate the value of the rf choke using the inductive reactance formula, XL = 2∏fL .for example here u can see a schematic which transmits in a frequency 100Mhz,there u can see a choke!
my friend gave me this way to find out the value of choke
" 10kΩ inductive reactance would be fine.
That translates to
XL = 2πfL
10kΩ = 10000Ω
10000Ω = 2π(100M)L
L = 10000 / (2*∏*1e8)
L = 1e4/ (2*∏*1e8)
L = (1/6) 1e-4
L = 0.16e-4
L = 16e-6
L = 16µH."
so there fore the vakue of the choke should be 16μH.
but can u guys please tell me how did that 10kΩ come from.how did he take the 10KΩ from the circuit! please help me!
my friend gave me this way to find out the value of choke
" 10kΩ inductive reactance would be fine.
That translates to
XL = 2πfL
10kΩ = 10000Ω
10000Ω = 2π(100M)L
L = 10000 / (2*∏*1e8)
L = 1e4/ (2*∏*1e8)
L = (1/6) 1e-4
L = 0.16e-4
L = 16e-6
L = 16µH."
so there fore the vakue of the choke should be 16μH.
but can u guys please tell me how did that 10kΩ come from.how did he take the 10KΩ from the circuit! please help me!
