This problem has been giving me trouble, first of all because I don't even understand the question.. I don't even know how to approach it
http://img14.imageshack.us/img14/3815/9copyxxl.jpg
http://img14.imageshack.us/img14/3815/9copyxxl.jpg
In part A), you don't have the right stuff in the parentheses in the denominator. When you flipped the fraction over, something went wrong.
That's exactly it. When you have a resistance R and a reactance X in series, the total impedance is in the form R + JX (the sum of the individual impedances). If they're in parallel, the form is 1/(1/R+1/jX) (the reciprocal of the sum of the reciprocals of the individual impedances), so to find the equivalent series. So you go through the manipulations as you did to find the impedance in the form it needs to be in to represent a pair of series impedances.If they are could you explain some logic in this problem to me at how you knew what to do...
For part a)
It's asking for an equivalent R'C' SERIES circuit... so this says
Z = R' + 1/jwC'?
Somehow I think this relates why you wanted me to separate my term into a+ib form
Yes, it was the pure resistance part the tipped me off! And, yes, you need to add an inductive reactance to cancel out the capacitive reactance (this is an example of resonance). Your inductance will have a reactance of jωL. So you need to find L such that jωL = the negative of the imaginary part of Z1.For part b)Not really sure about this one... what tipped you to only obtain a real answer? Was it the term 'pure resistance' in the problem?
Also, my teacher ran through the answer today with 3 minutes of class left... and in her answer she's messing around with jwL which suggests that shes adding an inductance of some type... I dunno
by Duane Benson
by Aaron Carman
by Aaron Carman