Impedance calculation

Discussion in 'Physics' started by sandhi, Dec 15, 2009.

Jan 28, 2009
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2. t_n_k AAC Fanatic!

Mar 6, 2009
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Not quite sure what the point of the exercise is, but I get the following relationship for Rf (which I haven't double checked)

$Rf=\frac{jXc}{1-\frac{jXc}{Rm+Rv-\frac{UgRm}{Um}}}$

where

$Xc=\frac{1}{\omega Ce}$

3. t_n_k AAC Fanatic!

Mar 6, 2009
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A point to note (if the relationship I gave is indeed correct) is that Rf should be purely resistive and hence the imaginary term(s) in the derived value of Rf should be zero. This means Um would have a complex value such that the aforementioned condition is met.