# How to convert basic gate to NAND gate

Discussion in 'General Electronics Chat' started by beginner123, Oct 3, 2010.

1. ### beginner123 Thread Starter New Member

Oct 3, 2010
1
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How to convert the following boolean expression X = AB + CD + AD' to 2- input NAND gate I had tried alot of time already, research on googles but still don't understand, can anyone help me?

I only know AB = (AB)' right if convert to NAND gate, so I get this boolean expression [(AB)'(CD)'(AD')']' does this correct? but it still 3 input, how to design the circuit with only 2-input NAND gate.

2. ### elisettynarendra Member

May 17, 2010
42
1
i will not give the solution rather i will give u a hint.
take out 'A' common u will be left with A(B+D')+CD . try modifying the equation rather than trying as it is..learn the basics.
use (AB)'=A'+B'
a+bc = (a+b)(a+c)
u will succeed.

Jul 23, 2009
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i forgot the laws of demorgan's law in simplifying that equation...

just subscribing this thread to know something.. thanks buddy..

4. ### Wendy Moderator

Mar 24, 2008
21,437
2,958
The example you gave, AB = (AB)', is seriously flawed, you want the output to be the same as it's inverted output? It is like saying 1=-1.