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No, it won't. The supply to the IC will not be regulated.Can I hook a zener diode with a series resistance of (33ohms) to the 11.1V and then connect to REGIN pin 5.5V tolerant pin??
Please help
11.1V -------- Zenerdiode (6.8V) ----- 33OHMS --- REGIN pin of IC.
Say there is a 0.1uF decoupling capacitor at the REGin pin.
Will the above scheme work , will there be appropriate transient protection especially during turn ON and OPFF of 11.1V supply??
Ok . I thought this pin was for measuring purposes. Forget also my first post, as I've seen now the BAT-pin needs to be connected to a low impedance source to measure correctly, not a resistive voltage divider...I am applying a stable voltage to the BAT pin anyways. SO there is no variation at the battery sense pin.
1.Where should be the problem in applying a voltage that is HALF of the maximum rating?Even if the voltage is not regulated this unregulated i/p will go to an Integrated voltage regulator.So in this case wont the scheme work.....
The peak current drawn by the system is not more than 1mA (dynamic). Average maximum current is 0.1mA. Drop across 33Ohms will be at max 30mV.
Got your point my scheme wont work at all .2. what's the 33R resistor for? If you just put the zener in series you drop the voltage to what you want. BUT, zener diodes have a minimum current for which the stabilization is effective. According to your datasheet the current can go down to 4uA in hibernation and 18uA in sleep mode. I don't know if a zener works still at this low current.
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