Hey thank you @djsfantasi. That means the current would not change while the load receive less voltage right?In a series circuit, current remains constant through the series circuit. The voltage drop is what changes across the load and resistor. So, while your load may receive the same current, it will not receive the same voltage.
if I is the current drawn by the load, R is the resistance of the resistor and Vs is the supply voltage, the resistor will drop IxR and your load will receive (Vs-(IxR)) volts.
If the load was a currentif we place an additional resistor in series with the load, can the load still draw the same current as it needed?
Thank you @dl324 , thank you for you help... How do I distinguish if it is a current sink or a resistance? Take motor as an example, it can be a current sink and resistance at the same time.Welcome to AAC!
If the load was a currentsourcesink and the power supply provided sufficient voltage for it to function, the current would stay the same. If the load was a resistance, the current would decrease.
It would be helpful if you posted a schematic for the situation so we can tell what the load is and give you a more specific answer.
Only if you raise the supply voltage.Assume we provide a load with its rated voltage, suppose it should draw the current it need at such voltage level. However, what if we place an additional resistor in series with the load, can the load still draw the same current as it needed?
Thank you @dl324 , thank you for you help... How do I distinguish if it is a current sink or a resistance? Take motor as an example, it can be a current sink and resistance at the same time.
btw... yesyes, I am going to post the schematic...
That circuit won't work well. You seem to be trying to convey that the load wants a 10V supply, but you're connecting it to a 1000V supply. You want to use a transistor to control power to the load, but the transistor can't be used as a switch. If you want the collector-emitter voltage to be 990V at 1A (leaving 10V for the load and ignoring the resistor which doesn't have a value), the transistor would need to dissipate 990W.I have a load in the collector of a BJT, the voltage it takes is depend on the current it draws by the amplified version of base current.
Yes I know it doesn't make sense in reality. However, In this circuit I just want to get my self clear about why some loads can control/draw a constant value of current from power supply while some cannot (a resistor is indeed a kind of load, but current drawn is depending on L but not R1). What makes a load dominate the control of current? Also, what will happen if 2 loads are run in series and they have different rating value of current at same voltage? Which one will dominate the control of current in such case?That circuit won't work well. You seem to be trying to convey that the load wants a 10V supply, but you're connecting it to a 1000V supply. You want to use a transistor to control power to the load, but the transistor can't be used as a switch. If you want the collector-emitter voltage to be 990V at 1A (leaving 10V for the load and ignoring the resistor which doesn't have a value), the transistor would need to dissipate 990W.
You're going to need to give some specific examples.However, In this circuit I just want to get my self clear about why some loads can control/draw a constant value of current from power supply while some cannot (a resistor is indeed a kind of load). What makes a load dominate the control of current?
Sure let me make it simple...You're going to need to give some specific examples.
Most circuits are designed for a specific range of input voltages. Going outside of that range shouldn't even be considered unless you think you know more than the person who designed it.
I don't have any experience wiring motors like that. I'd say the current won't be 1A or 2A and they won't share voltage equally.When there are 2 motors then which one "take the control"?
Not if it is connected to a constant voltage source.Assume we provide a load with its rated voltage, suppose it should draw the current it need at such voltage level. However, what if we place an additional resistor in series with the load, can the load still draw the same current as it needed?