- (5) As above, show the truth table, Boolean equation, and circuit diagram for a circuit that will take 5 inputs ABCDE and output a 1 if the pattern contains exactly 2 bits.
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0 0 0 0 0 | 0
0 0 0 0 1 | 0
0 0 0 1 0 | 0
0 0 0 1 1 | 1
0 0 1 0 0 | 0
0 0 1 0 1 | 1
0 0 1 1 0 | 1
0 0 1 1 1 | 0
0 1 0 0 0 | 0
0 1 0 0 1 | 1
0 1 0 1 0 | 1
0 1 0 1 1 | 0
0 1 1 0 0 | 1
0 1 1 0 1 | 0
0 1 1 1 0 | 0
0 1 1 1 1 | 0
1 0 0 0 0 | 0
1 0 0 0 1 | 1
1 0 0 1 0 | 1
1 0 0 1 1 | 0
1 0 1 0 0 | 1
1 0 1 0 1 | 0
1 0 1 1 0 | 0
1 0 1 1 1 | 0
1 1 0 0 0 | 1
1 1 0 0 1 | 0
1 1 0 1 0 | 0
1 1 0 1 1 | 0
1 1 1 0 0 | 0
1 1 1 0 1 | 0
1 1 1 1 0 | 0
1 1 1 1 1 | 0
- F = ABC'D'E' + AB'CD'E' + AB'C'DE' + AB'C'D'E + A'BCD'E' + A'BC'DE' + A'BC'D'E + A'B'CDE' + A'B'CD'E + A'B'C'
So anyway, if anyone is able to point me in the right direction or maybe fill me in on errors in logic I may have made it would be very helpful. Really, any constructive criticism on the matter would be awesome.