Hello I'm working with DC High Voltage supplies to power a Geiger tube and am having a little bit of trouble understanding them. I really just have 3 questions:
Example Circuit:
1.) When using a diode ladder like in this example circuit, how do you determine what is the maximum voltage it can output? I mean, in general, you are charging the first capacitor to some maximum voltage Vo, and then each step on the ladder doubles it. I am having a good deal of difficulty figuring out what that first initial voltage is. The power line for the circuit is +5v, and that is applied across an inductor which is switched to ground to get an AC current flowing to be used to climb the ladder. How do you calculate the peak AC voltage that will be multiplied as it goes up the ladder?
2.) This circuit is a rather wierd one as it takes feedback from the lowest part of the ladder (thats their way to make sure the not much current leaks through the larger resistor voltage divider back to ground). Most circuits that I have seen take feedback from the highest point of the ladder. I have no idea how the MAXIM ciruit controlls the voltage at the top of the ladder, maybe it just limits the peak AC Vo by the resistor divider and the low level of the ladder and assumes the voltage will multiply up the ladder in perfect doubles?
3.) In our design, there is no Schmidt Trigger or comparator. We just have a single IC that takes in a reference voltage (From a resistor divider from the top of the ladder). And when that reference voltage drops below a certain value, it sends out a 45kHz square wave (0-Vcc) to the base of the MOSFET and hence toggles the mosfet to generate the AC voltage to climb the ladder. This way, if we want the voltage to stay at 400, the divider at the top of the ladder is set such that it puts in the reference required to turn on the IC-oscillator when the top of the ladder reaches 400V.
In the MAXIM circuit, this feedback is somehow used to create an oscillating square wave to the base of the MOSFET.
How does this particular method oscillate the MOSFET?
Any explaination on this stuff would be greatly appreciated.
Example Circuit:
1.) When using a diode ladder like in this example circuit, how do you determine what is the maximum voltage it can output? I mean, in general, you are charging the first capacitor to some maximum voltage Vo, and then each step on the ladder doubles it. I am having a good deal of difficulty figuring out what that first initial voltage is. The power line for the circuit is +5v, and that is applied across an inductor which is switched to ground to get an AC current flowing to be used to climb the ladder. How do you calculate the peak AC voltage that will be multiplied as it goes up the ladder?
2.) This circuit is a rather wierd one as it takes feedback from the lowest part of the ladder (thats their way to make sure the not much current leaks through the larger resistor voltage divider back to ground). Most circuits that I have seen take feedback from the highest point of the ladder. I have no idea how the MAXIM ciruit controlls the voltage at the top of the ladder, maybe it just limits the peak AC Vo by the resistor divider and the low level of the ladder and assumes the voltage will multiply up the ladder in perfect doubles?
3.) In our design, there is no Schmidt Trigger or comparator. We just have a single IC that takes in a reference voltage (From a resistor divider from the top of the ladder). And when that reference voltage drops below a certain value, it sends out a 45kHz square wave (0-Vcc) to the base of the MOSFET and hence toggles the mosfet to generate the AC voltage to climb the ladder. This way, if we want the voltage to stay at 400, the divider at the top of the ladder is set such that it puts in the reference required to turn on the IC-oscillator when the top of the ladder reaches 400V.
In the MAXIM circuit, this feedback is somehow used to create an oscillating square wave to the base of the MOSFET.
How does this particular method oscillate the MOSFET?
Any explaination on this stuff would be greatly appreciated.
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