could some one lease give me a helping hand with this please 17) A circuit consists of a 0.16μf capacitor connected across a 20V, 1 kHz supply. Also in parallel with the capacitor there is a 1kΩ resistor in series with a 0.18H coil. Calculate The current drawn from the supply The phase angle of this current (Use the j operator in your calculation.)
Calculate the impedance of the inductor and capacitor at 1KHz (source frequency) and then find the equivalent impedance of the circuit . Then divide the equivalent resistance of the circuit form the voltage to find the current.
thanks for the reply. ive come up with the answer X_(c ) = 1/2πfc = X_(c ) = 1/(2×π×1000×0.00000016) = 994.71 ohms X_l=2πfl=2 × π ×1000 ×0.18 = 1130.97 ohms 1/(1/((1130.97+1000))+ 1/994.71) = 678 Ω 20/678 = 0.029 A sorry about the poor formula but its was done in microsoft equation wizard and hasent came out that well on this site. im still stuck with part b and with what the j operator bit means.
Z= 691.55678 ohms I = 0.02892 amps Phase angle 11'degrees leading because capacitor is taking more of the current than the inductor. ( tan of X / R . = 136.26/678 )