Hello

Im having trouble with this integral, and im sure there is a way to do it quickly...anyway, here is the equation:

∫\( \frac{1-y}{3} e\frac{(1-y)^2}{2} dy \)

I want to do the *trick* where you start with y = and then diffentiate and then just change the y = formula...but I cant remember how to do it...

 

make a substitution of a new variable such that ...

v={(1-y)^2}/2
dv=?? dy

and so on ....

 

∫\(\frac{(1-y)}{3}\)e\(^{\frac{(1-y)^{2}}{2}}\)dy=-\(\frac{1}{3}\)∫e\(^{\frac{(1-y)^{2}}{2}}\)d(\(\frac{(1-y)^{2}}{2}\))

make a substitution of a new variable such that ...

v=\(\frac{(1-y)^{2}}{2}\)
that will be
-\(\frac{1}{3}\)∫e\(^{v}\)dv

and so on ....