Can a resonance circuit serve as a filter? How?
I know it does but don't know much description, if someone can describe it in simple words...thanks

 

Why don't you go back and at least attempt to answer some of the clarifying questions that have been asked of you in prior threads you've started where you are just asking someone to provide an answer to your homework questions?

 

Hello,

Can you show us what you have done upto now?

Bertus

PS PLEASE READ - Posting Questions in the Homework Help Forum

 

Similar question was asked before?

 

Hello,

Have a look in this chapter of the eBook:
Chapter 6: RESONANCE

Bertus

 

Similar question was asked before?

Yep ... http://forum.allaboutcircuits.com/showthread.php?t=74789

The answer to that question should have guided you to answer your current question. You have been provided with another reference to read.

If your interested in just the answers, google "electronics tutoring" and you will be provided with a list of fee based tutoring services.

 

I wanted the answer in simple words, so I could have understand it better...Short and simple

 

Hello,

We are not an answering service.
You will have to show us what you have done.
That way we can see if you are understanding the theory.

Bertus

 

Hello,

We are not an answering service.
You will have to show us what you have done.
That way we can see if you are understanding the theory.

Bertus

oo..sorry I didnt mean that...I was just trying to get help with the Resonance circuit.
I had lesson abt the high pass and low pass filter. And I wanted to find out Resonance is related to filter
I learned about filters can be passive and active on my class. Active filters are better because it works as amplifier also

 

I wanted the answer in simple words, so I could have understand it better...Short and simple

Then why don't you give us YOUR present understanding, however flawed it may or may not be, so that we can address your specific issues.

 

I was jsut trying to get help to understand better...like on my previous questions...I asked here,,,I received lot of responses and which helped me to understand the topic better...

 

This is what I know on Resonance.
At Series Resonance, XL=XC, ZT=R
Resonance occurs at a specific frequency f0= 1/2π√ (LC)
At resonance frequency circuit shows filtering effects.

 

Hello,

Did you read the chapter of the eBook I gave you.
There is all about resonance and filtering and the influence of the Q factor in there.

Bertus

 

Q1) What is the equation for the capacitive reactance as a function of frequency?

Q2) What is the equation for the inductive reactance as a function of frequency?

Q3) At what frequency will the magnitude of the capacitive and inductive reactances be equal? This is the resonant frequency.

Q4) In a series R, L, C circuit, how do the resistance and the two reactances add?

Q5) What does this reduce to at the resonant frequency?

 

Q1) What is the equation for the capacitive reactance as a function of frequency?

Q2) What is the equation for the inductive reactance as a function of frequency?

Q3) At what frequency will the magnitude of the capacitive and inductive reactances be equal? This is the resonant frequency.

Q4) In a series R, L, C circuit, how do the resistance and the two reactances add?

Q5) What does this reduce to at the resonant frequency?

1. XC=1/2pifc
2. XL=2pifL
3. when f0= 1/2π√ (LC)
4. ZT=√R^2+(XL-XC)^2
5.At resonance XL=XC and ZT=R

 

So considering the answers to those questions, what's one observation you can make about the effect of being at the resonant frequency versus not being at that frequency in a series RLC circuit?

 

So considering the answers to those questions, what's one observation you can make about the effect of being at the resonant frequency versus not being at that frequency in a series RLC circuit?

At the resonance frequency current of series ckt is at maximum and the gain is maximum also

 

what happen to the filter if R1 is about 1kohm?
http://i50.tinypic.com/xawenc.png

 

What is it with you?! Here you go asking us to just provide the answer to your homework again. You need to first show YOUR honest effort to work the problem and ask specific questions about the points you are having difficulty with. But it will have to be someone else that responds, because I'm done with you.

 

oo...sorry i thought the question was related to the question I asked in this thread...