y'' - 2y' = 12e^2x -8e^-2.

I have found the complementary function, which is Ae^2x + B but im not sure what my trial solution should be to find the particular solution.

I tried y = axe^2x - be^-2x, for the trial solution and had a nice answer. I don't think this is correct however...please let me know! Thankyou.