Mojo,I dont have an idea on how to assign values for this very simple circuit (pushon-pushoff). Anybody can do will be much appreciated. I will apply it to my motorcycle to cut the ignition coil (12V) while on parking.
My friend told me its not the ignition line to be cut, its the CDI line. If that so, I need an ordinary 12 volts relay and I will try to use those values.Mojo,
If you look back to my previous post (#6) you will have values that might work. It's the same circuit only redrawn and with the extra set of SPDT contacts added to make it usable. The relay you use depends on the amount current it's contacts can handle, and that depends on the amount of current your ignition circuit draws. Do you know what that is?
Ken
A 12V relay in that circuit will not work a 12v battery supply. The concept is that the relay coil voltage is 1/2 the supply voltage. An explanation: http://www.oldradio.com/current/pushon-pushoff.htmMy friend told me its not the ignition line to be cut, its the CDI line. If that so, I need an ordinary 12 volts relay and I will try to use those values.
Thanks Ken
Ken: thanks for showing that -- I hadn't seen it before and it's just, well, clever. It only consumes 0.3 W when it's on -- not for battery use, but OK for a line-powered device.This is a cute circuit to get a push on/push off relay function. The relay coil voltage should be half that of the supply (5-6V for a 12v supply), and the resistors should be equal to the relay's coil resistance.
ken
Thank you Ken, it is noted.A 12V relay in that circuit will not work a 12v battery supply. The concept is that the relay coil voltage is 1/2 the supply voltage. An explanation: http://www.oldradio.com/current/pushon-pushoff.htm
You would need a 5V or 6V coil relay.
Ken