help with inductor

Discussion in 'Homework Help' started by acidknack, Jul 27, 2005.

  1. acidknack

    Thread Starter New Member

    Jul 26, 2005
    an inductor has an internal resistance of 25 Ω and quality factor of 10 at a resonance frequency of 10kHz is fed from a 100V supply. calculate the following:

    i) Value of series capacitance required to produce resonance with the coil
    ii) The inductance of the coil
    iii) Q0 using L/C ratio
    iv) Voltage across the capacitor at resonance
    v) Voltage across the coil at resonance

    can anyone help me start? i'm at a loss. thank you.
  2. n9xv

    Senior Member

    Jan 18, 2005
    Q = XL / R(DC)

    Q = Quality factor
    XL = inductive reactance
    R(DC) = DC resistance

    So, if Q = 10 and R(DC) = 25 then XL = 2500-ohms.

    Now you have inductive reactance and can solve for inductance L.

    XL = 6.28*F*L

    So, L = XL / 6.28*F